MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The reaction of an amine with chloroform and ethanolic KOH to form an isocyanide is known as the carbylamine reaction. This reaction is a characteristic test given only by primary aliphatic and primary aromatic amines. Among the given options, benzenamine (aniline) is a primary aromatic amine, while N-methylaniline and ethylethanamine are secondary amines, and N,N-dimethylaniline is a tertiary amine. Therefore, benzenamine reacts with chloroform and ethanolic KOH to form phenyl isocyanide (an aryl isocyanide). C_6H_5NH_2 + CHCl_3 + 3KOH C_6H_5NC + 3KCl + 3H_2O Answer: Benzenamine