MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The given compound is ^ 1 CH _2 = ^ 2 CH - ^ 3 CH _2 - ^ 4 CH _2 - ^ 5 C ^ 6 CH . The hybridization of a carbon atom is determined by the number of sigma bonds it forms. Carbon atom C_2 is bonded to one carbon atom via a double bond, one carbon atom via a single bond, and one hydrogen atom via a single bond. It forms 3 sigma bonds and 1 pi bond. Thus, C_2 is sp^2 hybridized. Carbon atom C_3 is bonded to two carbon atoms via single bonds and two hydrogen atoms via single bonds. It forms 4 sigma bonds and 0 pi bonds. Thus, C_3 is sp^3 hybridized. Therefore, the C_2 - C_3 bond is formed by the overlap of sp^2 and sp^3 hybridized orbitals, making it an sp^2 - sp^3 type bond. Answer: sp^2 - sp^3