MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

Given half-life of the first order reaction, t_ 1/2 = 1 minute 40 seconds Converting to seconds, t_ 1/2 = 60 + 40 = 100 s For a first order reaction, the rate constant k is given by the relation: k = 0.693 t_ 1/2 Substituting the value of t_ 1/2 : k = 0.693 100 s k = 6.93 10^ -3 s ^ -1 Answer: 6.93 10^ -3 \ s ^ -1