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MHT CET Chemistry Chemical Kinetics 2026 MHT CET 2026 (19 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

Rate constant of decomposition of hydrogen peroxide is 0.0204\ minutes ^ -1 , calculate half life of reaction.

Options

  1. A. 17.56 minutes
  2. B. 33.97 minutes
  3. C. 51.50 minutes
  4. D. 68.70 minutes

Answer

B. 33.97 minutes

Step-by-step solution

The unit of the rate constant is minutes ^ -1 , which indicates that the decomposition of hydrogen peroxide is a first-order reaction. For a first-order reaction, the half-life is given by: t_ 1/2 = 0.693 k Substituting the given value of k = 0.0204\ minutes ^ -1 : t_ 1/2 = 0.693 0.0204 t_ 1/2 = 33.97\ minutes Answer: 33.97 minutes

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