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MHT CET Chemistry Chemical Kinetics 2026 MHT CET 2026 (19 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

A first order reaction take 30 minutes for 75\% decomposition, calculate its rate constant ?

Options

  1. A. 0.0238\ minute ^ -1
  2. B. 0.0463\ minute ^ -1
  3. C. 0.0715\ minute ^ -1
  4. D. 0.0957\ minute ^ -1

Answer

B. 0.0463\ minute ^ -1

Step-by-step solution

For a first order reaction, the integrated rate law is given by: k = 2.303 t ( a a-x ) Given that the reaction is 75\% complete in 30 minutes: t = 30\ minutes x = 0.75a a - x = a - 0.75a = 0.25a Substituting these values into the rate equation: k = 2.303 30 ( a 0.25a ) k = 2.303 30 (4) k = 2.303 30 0.6020 k = 1.386 30 = 0.0462\ minute ^ -1 Alternatively, 75\% decomposition corresponds to two half-lives: t_ 75\% = 2 t_ 1/2 30 = 2 t_ 1/2 t_ 1/2 = 15\ minutes k = 0.693 t_ 1/2 = 0.693 15 = 0.0462\ minute ^ -1 The closest given option is 0.0463\ minute ^ -1 . Answer: 0.0463\ minute ^ -1

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