Question
For the reaction 2 NOBr _ (g) 2 NO _ (g) + Br _ 2(g) , rate law is r = k[ NOBr ]^2. Rate constant is 1.62\ M s ^ -1 and concentration of NOBr is 5 10^ -3 \ M , What is rate of reaction?
MHT CET
Chemistry
Chemical Kinetics
2026
MHT CET 2026 (18 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 4.05 10^ -5 \ M s ^ -1
- B. 6.48 10^ -6 \ M s ^ -1
- C. 2.12 10^ -5 \ M s ^ -1
- D. 8.63 10^ -6 \ M s ^ -1
Answer
A. 4.05 10^ -5 \ M s ^ -1
Step-by-step solution
Given rate law is r = k[ NOBr ]^2 Substituting the given values: r = 1.62 (5 10^ -3 )^2 r = 1.62 25 10^ -6 r = 40.5 10^ -6 r = 4.05 10^ -5 \ M s ^ -1 Answer: 4.05 10^ -5 \ M s ^ -1
Related: Chemistry — Chemical Kinetics · All PYQ Banks