Question
In a first order reaction 20 millimole of reactant is lowered to 10 millimole in 0.3010 minute. Find rate constant of the reaction?
MHT CET
Chemistry
Chemical Kinetics
2026
MHT CET 2026 (18 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 3.010\ minute ^ -1
- B. 0.602\ minute ^ -1
- C. 2.303\ minute ^ -1
- D. 0.301\ minute ^ -1
Answer
C. 2.303\ minute ^ -1
Step-by-step solution
For a first order reaction, the rate constant k is given by the expression: k = 2.303 t ( a a - x ) Given: Initial amount, a = 20 millimole Amount after time t, a - x = 10 millimole Time, t = 0.3010 minute Substituting the given values into the equation: k = 2.303 0.3010 ( 20 10 ) k = 2.303 0.3010 2 Using the standard value 2 = 0.3010: k = 2.303 0.3010 0.3010 k = 2.303\ minute ^ -1 Answer: 2.303\ minute ^ -1
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