Question
In first order reaction 20 millimole of reactant is reduced to 10 millimole in 1 151 minute. Find rate constant.
MHT CET
Chemistry
Chemical Kinetics
2026
MHT CET 2026 (17 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 0 6023 minute ^ -1
- B. 6 120 minute ^ -1
- C. 0 3010 minute ^ -1
- D. 2 010 minute ^ -1
Answer
A. 0 6023 minute ^ -1
Step-by-step solution
For a first order reaction, the rate constant is given by k = 2 303 t ( a a-x ) Substituting the given values a = 20 millimole, a-x = 10 millimole, and t = 1 151 minute: k = 2 303 1 151 ( 20 10 ) k = 2 303 1 151 2 k = 2 303 0 3010 1 151 k = 0 6023 minute ^ -1 Answer: 0 6023 minute ^ -1
Related: Chemistry — Chemical Kinetics · All PYQ Banks