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MHT CET Chemistry Chemical Kinetics 2026 MHT CET 2026 (17 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

For the reaction 2 NOBr _ (g) 2 NO _ (g) + Br _ 2(g) rate law is r = k[ NOBr ]^2, if rate constant is 1 62 mol dm ^ -3 s ^ -1 and concentration of NOBr is 2 10^ -3 mol L ^ -1 . What is the rate of reaction ?

Options

  1. A. 4 05 10^ -5 mol dm ^ -3 s ^ -1
  2. B. 6 48 10^ -6 mol dm ^ -3 s ^ -1
  3. C. 2 12 10^ -5 mol dm ^ -3 s ^ -1
  4. D. 8 63 10^ -6 mol dm ^ -3 s ^ -1

Answer

B. 6 48 10^ -6 mol dm ^ -3 s ^ -1

Step-by-step solution

Given rate law is r = k[ NOBr ]^2 Substituting the given values: k = 1.62 [ NOBr ] = 2 10^ -3 mol L ^ -1 = 2 10^ -3 mol dm ^ -3 r = 1.62 (2 10^ -3 )^2 r = 1.62 4 10^ -6 r = 6.48 10^ -6 mol dm ^ -3 s ^ -1 Answer: 6 48 10^ -6 mol dm ^ -3 s ^ -1

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