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MHT CET Chemistry Chemical Kinetics 2026 MHT CET 2026 (16 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

The rate constant for the reaction 2 N _2 O _5 4 NO _2 + O _2 is 3.0 10^ -5 \ s ^ -1 . If the rate is 2.4 10^ -5 \ mole L ^ -1 \ s ^ -1 then the concentration of N _2 O _5\,( mol L ^ -1 ) is

Options

  1. A. 1.4
  2. B. 1.2
  3. C. 0.04
  4. D. 0.8

Answer

D. 0.8

Step-by-step solution

From the unit of the rate constant ( s ^ -1 ), we can determine that the given reaction is a first-order reaction. For a first-order reaction, the rate law is expressed as: Rate = k[ N _2 O _5] Given values are: Rate = 2.4 10^ -5 mole L ^ -1 s ^ -1 k = 3.0 10^ -5 s ^ -1 Substituting these values into the rate equation: 2.4 10^ -5 = 3.0 10^ -5 [ N _2 O _5] Solving for the concentration of N _2 O _5: [ N _2 O _5] = 2.4 10^ -5 3.0 10^ -5 [ N _2 O _5] = 2.4 3.0 [ N _2 O _5] = 0.8 mol L ^ -1 Answer: 0.8

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