The rate of the reaction 2A + 3B 2C + D is 6 10^ -4 mol dm ^ -3 s ^ -1 , when [A] = [B] = 0.3 mol dm ^ -3 . If the reaction is of first order for A and zeroth order for B, then find the rate constant.

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Correct answer: B. 2 10^ -3 s ^ -1

The rate law for the given reaction is written as: Rate = k[A]^1[B]^0 Substituting the given values into the rate law equation: 6 10^ -4 = k(0.3)^1(0.3)^0 6 10^ -4 = k 0.3 k = 6 10^ -4 0.3 k = 2 10^ -3 s ^ -1 Answer: 2 10^ -3 s ^ -1

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