The rate constant for a first order reaction is 60 s ^ -1 . How much time will it take to reduce the concentration of the reactant to 1/20^ th of its initial value?

Question

Quantrex Academy · Accepted Answer

Correct answer: C. 0.0499 s

For a first order reaction, the time required is given by the integrated rate equation: t = 2.303 k ( [R]_0 [R] ) Given k = 60 s ^ -1 and the final concentration [R] = [R]_0 20 . Substituting the values into the equation: t = 2.303 60 ( [R]_0 [R]_0 20 ) t = 2.303 60 (20) Using (20) = (2 10) = 2 + 10 = 0.3010 + 1 = 1.3010: t = 2.303 1.3010 60 t = 2.9962 60 t 0.0499 s Answer: 0.0499 s

MHT CET Chemistry Question (2026) — Solution

Question

Options

Answer

Step-by-step solution