MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

Paramagnetic ions are those that contain at least one unpaired electron in their electronic configuration. Writing the outer electronic configurations of the given ions: V ^ +2 : [ Ar ] 3d^ 3 (3 unpaired electrons, paramagnetic) Co ^ +2 : [ Ar ] 3d^ 7 (3 unpaired electrons, paramagnetic) Ti ^ +4 : [ Ar ] 3d^ 0 (0 unpaired electrons, diamagnetic) Ni ^ +2 : [ Ar ] 3d^ 8 (2 unpaired electrons, paramagnetic) Cu ^ +2 : [ Ar ] 3d^ 9 (1 unpaired electron, paramagnetic) Zn ^ +2 : [ Ar ] 3d^ 10 (0 unpaired electrons, diamagnetic) Ti ^ +2 : [ Ar ] 3d^ 2 (2 unpaired electrons, paramagnetic) Cu ^ +2 : [ Ar ] 3d^ 9 (1 unpaired electron, paramagnetic) Mn ^ +3 : [ Ar ] 3d^ 4 (4 unpaired electrons, paramagnetic) Sc ^ +3 : [ Ar ] 3d^ 0 (0 unpaired electrons, diamagnetic) Ti ^ +3 : [ Ar ] 3d^ 1 (1 unpaired electron, paramagnetic) V ^ +3 : [ Ar ] 3d^ 2 (2 unpaired electrons, paramagnetic) The set containing only paramagnetic ions is Ti ^ +2 , Cu ^ +2 , Mn ^ +3 . Answer: Ti ^ +2 , Cu ^ +2 , Mn ^ +3