Question
Determine the electrode potential of Sn ^ 2+ (0.01 M )\ |\ Sn(s) at 25^ C if E^ _ Sn is -0.136 V.
Determine the electrode potential of Sn ^ 2+ (0.01 M )\ |\ Sn(s) at 25^ C if E^ _ Sn is -0.136 V.
C. -0.195 V
The reduction half-reaction is Sn ^ 2+ + 2e^ - Sn(s) . Using the Nernst equation: E = E^ - 0.0591 n 1 [ Sn ^ 2+ ] Substituting the given values (n = 2, [ Sn ^ 2+ ] = 0.01 M , E^ = -0.136 V ): E = -0.136 - 0.0591 2 1 0.01 E = -0.136 - 0.02955 (100) E = -0.136 - 0.02955 2 E = -0.136 - 0.0591 E = -0.1951 V -0.195 V Answer: -0.195 V
Related: Chemistry — Electrochemistry · All PYQ Banks