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MHT CET Chemistry Electrochemistry 2026 MHT CET 2026 (20 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

What is the molar conductivity of 0.02 M KI solution if its conductivity is 4.37 10^ -4 \, ^ -1 \, cm ^ -1 ?

Options

  1. A. 8.74\ ^ -1 \, cm ^2 mol ^ -1
  2. B. 21.85\ ^ -1 \, cm ^2 mol ^ -1
  3. C. 43.70\ ^ -1 \, cm ^2 mol ^ -1
  4. D. 13.65\ ^ -1 \, cm ^2 mol ^ -1

Answer

B. 21.85\ ^ -1 \, cm ^2 mol ^ -1

Step-by-step solution

Given: Conductivity, = 4.37 10^ -4 \, ^ -1 \, cm ^ -1 Molarity, M = 0.02 \, M The formula for molar conductivity is: _m = 1000 M Substituting the given values: _m = 4.37 10^ -4 1000 0.02 _m = 0.437 0.02 _m = 21.85 \, ^ -1 \, cm ^2 \, mol ^ -1 Answer: 21.85\ ^ -1 \, cm ^2 mol ^ -1

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