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MHT CET Chemistry Electrochemistry 2026 MHT CET 2026 (19 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

What is molar conductivity of CH _3 COOH at zero concentration if the molar conductivities of H _2 SO _4, K _2 SO _4 and CH _3 COOK at zero concentrations are respectively x, y and z ^ -1 cm ^2 mol ^ -1 ?

Options

  1. A. (x - y) 2 + z
  2. B. (x - y + 2z)
  3. C. (x + y - z)
  4. D. (x - y) 2 + 2z

Answer

A. (x - y) 2 + z

Step-by-step solution

By Kohlrausch's law of independent migration of ions: ^ _m(H_2SO_4) = 2 ^ (H^+) + ^ (SO_4^ 2- ) = x ^ _m(K_2SO_4) = 2 ^ (K^+) + ^ (SO_4^ 2- ) = y ^ _m(CH_3COOK) = ^ (CH_3COO^-) + ^ (K^+) = z The molar conductivity of CH_3COOH at zero concentration is: ^ _m(CH_3COOH) = ^ (CH_3COO^-) + ^ (H^+) Subtracting the second equation from the first: x - y = 2 ^ (H^+) - 2 ^ (K^+) x - y 2 = ^ (H^+) - ^ (K^+) Adding this to the third equation: x - y 2 + z = [ ^ (H^+) - ^ (K^+)] + [ ^ (CH_3COO^-) + ^ (K^+)] x - y 2 + z = ^ (CH_3COO^-) + ^ (H^+) Therefore, ^ _m(CH_3COOH) = x - y 2 + z

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