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MHT CET Chemistry Electrochemistry 2026 MHT CET 2026 (19 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

What is the conductivity of 0.02\ M \ AgNO _3 solution having cell constant 1.2\ cm ^ -1 and resistance 95.0\ ohms ?

Options

  1. A. 1.140 10^ -2 \ ^ -1 \ cm ^ -1
  2. B. 1.263 10^ -2 \ ^ -1 \ cm ^ -1
  3. C. 1.340 10^ -2 \ ^ -1 \ cm ^ -1
  4. D. 1.463 10^ -2 \ ^ -1 \ cm ^ -1

Answer

B. 1.263 10^ -2 \ ^ -1 \ cm ^ -1

Step-by-step solution

Given: Resistance, R = 95.0\ Cell constant, G^ * = 1.2\ cm ^ -1 The conductivity is given by the relation: = 1 R G^ * Substituting the given values: = 1 95.0 1.2 = 0.01263\ ^ -1 \ cm ^ -1 = 1.263 10^ -2 \ ^ -1 \ cm ^ -1 Answer: 1.263 10^ -2 \ ^ -1 \ cm ^ -1

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