Question
The conductivity of 0.02 M of KCl solution at 298 K is 0.0123 ohm ^ -1 \ cm ^ -1 . If the resistance of the cell containing this solution is 120 ohms, what is the value of the cell constant ?
MHT CET
Chemistry
Electrochemistry
2026
MHT CET 2026 (17 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1.050\ cm ^ -1
- B. 1.025\ cm ^ -1
- C. 1.376\ cm ^ -1
- D. 1.476\ cm ^ -1
Answer
D. 1.476\ cm ^ -1
Step-by-step solution
The relation between conductivity , resistance R, and cell constant G^* is given by: G^* = R Given: = 0.0123 ohm ^ -1 \ cm ^ -1 R = 120 ohms Substituting the values: G^* = 0.0123 120 G^* = 1.476 cm ^ -1 Answer: 1.476\ cm ^ -1
Related: Chemistry — Electrochemistry · All PYQ Banks