Question
If the emf of cell, Cu _ (s) Cu ^ 2+ _ (1M) \| Ag ^ + _ (1M) Ag is 0.463 V at 25\ ^ C and standard potential of Cu electrode is 0.337 V. Find the standard potential of Ag electrode
If the emf of cell, Cu _ (s) Cu ^ 2+ _ (1M) \| Ag ^ + _ (1M) Ag is 0.463 V at 25\ ^ C and standard potential of Cu electrode is 0.337 V. Find the standard potential of Ag electrode
C. 0.8\ V
The cell representation is Cu _ (s) Cu ^ 2+ _ (1M) \| Ag ^ + _ (1M) Ag . Since the concentrations of the ions are 1\ M , the given emf is the standard emf of the cell, E^ _ cell = 0.463\ V . The standard reduction potential of the anode (Cu) is E^ _ Cu ^ 2+ / Cu = 0.337\ V . Using the relation for standard cell potential: E^ _ cell = E^ _ cathode - E^ _ anode E^ _ cell = E^ _ Ag ^ + / Ag - E^ _ Cu ^ 2+ / Cu Substituting the given values: 0.463 = E^ _ Ag ^ + / Ag - 0.337 E^ _ Ag ^ + / Ag = 0.463 + 0.337 = 0.800\ V The standard potential of the Ag electrode is 0.8\ V . Answer: 0.8\ V
Related: Chemistry — Electrochemistry · All PYQ Banks