Question
The E^0_ cell of Al _ (s) | Al ^ 3+ (1 M ) || Pb ^ 2+ (1 M ) | Pb _ (s) cell is 1.5 V if E^0_ Pb is -0.14 V then E^0_ Al will be
MHT CET
Chemistry
Electrochemistry
2026
MHT CET 2026 (15 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1.64 V
- B. -1.64 V
- C. 1.36 V
- D. -1.36 V
Answer
B. -1.64 V
Step-by-step solution
The standard cell potential is given by the difference between the standard reduction potentials of the cathode and the anode. E^ 0 _ cell = E^ 0 _ cathode - E^ 0 _ anode From the given cell representation, aluminium (Al) undergoes oxidation and acts as the anode, while lead (Pb) undergoes reduction and acts as the cathode. E^ 0 _ cell = E^ 0 _ Pb ^ 2+ / Pb - E^ 0 _ Al ^ 3+ / Al Substituting the given values: 1.5 = -0.14 - E^ 0 _ Al ^ 3+ / Al E^ 0 _ Al ^ 3+ / Al = -0.14 - 1.5 = -1.64 V Answer: -1.64 V
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