Question
Calculate the concentration of silver nitrate solution if molar conductivity and conductivity of silver nitrate at 25^ are respectively 120 ohm^ -1 cm^2 mol^ -1 and 0.0024 ohm^ -1 cm^ -1 .
MHT CET
Chemistry
Electrochemistry
2026
MHT CET 2026 (15 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 0.01 M
- B. 0.02 M
- C. 0.03 M
- D. 0.04 M
Answer
B. 0.02 M
Step-by-step solution
The relationship between molar conductivity _m, conductivity , and concentration C in molarity is given by: _m = 1000 C Rearranging the formula to solve for concentration C: C = 1000 _m Substituting the given values = 0.0024 ohm ^ -1 cm ^ -1 and _m = 120 ohm ^ -1 cm ^2 mol ^ -1 : C = 0.0024 1000 120 C = 2.4 120 C = 0.02 M Answer: 0.02 M
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