Question
The molar conductivity of 0.04 M AB _2 type salt solution at 300 K is 200\, ^ -1 cm ^2 mol ^ -1 . Find the conductivity.
MHT CET
Chemistry
Electrochemistry
2026
MHT CET 2026 (15 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 0.006\, ^ -1 cm ^ -1
- B. 0.008\, ^ -1 cm ^ -1
- C. 0.01\, ^ -1 cm ^ -1
- D. 0.015\, ^ -1 cm ^ -1
Answer
B. 0.008\, ^ -1 cm ^ -1
Step-by-step solution
The relation between molar conductivity _m, conductivity , and molarity M is given by: _m = 1000 M Given: _m = 200\, ^ -1 cm ^2 mol ^ -1 M = 0.04 M Substituting the given values into the formula: 200 = 1000 0.04 = 200 0.04 1000 = 8 1000 = 0.008\, ^ -1 cm ^ -1 Answer: 0.008\, ^ -1 cm ^ -1
Related: Chemistry — Electrochemistry · All PYQ Banks