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MHT CET Chemistry Electrochemistry 2026 MHT CET 2026 (13 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

Calculate the molar conductivity of 0.2 M KCl solution at 298 K (k = 0.0248 \ ^ -1 cm^ -1 )

Options

  1. A. 143 \ ^ -1 cm^2 mol^ -1
  2. B. 98 \ ^ -1 cm^2 mol^ -1
  3. C. 124 \ ^ -1 cm^2 mol^ -1
  4. D. 87 \ ^ -1 cm^2 mol^ -1

Answer

C. 124 \ ^ -1 cm^2 mol^ -1

Step-by-step solution

Given concentration C = 0.2 M and conductivity k = 0.0248 \ ^ -1 cm^ -1 . The formula for molar conductivity is _m = k 1000 C . Substituting the given values: _m = 0.0248 1000 0.2 _m = 24.8 0.2 = 124 \ ^ -1 cm^2 mol^ -1 . Answer: 124 \ ^ -1 cm^2 mol^ -1

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