Question
At 298 K, the specific conductance ( ) of a 0.0020 M NaCl solution is 2.50 10^ -4 S cm ^ -1 . Calculate the molar conductivity ( _m) of the solution in S cm ^2 mol ^ -1 .
MHT CET
Chemistry
Electrochemistry
2026
MHT CET 2026 (11 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 125
- B. 62.5
- C. 12.5
- D. 250
Answer
A. 125
Step-by-step solution
Given: = 2.50 10^ -4 S cm ^ -1 C = 0.0020 M The molar conductivity _m is given by the formula: _m = 1000 C Substituting the given values: _m = 2.50 10^ -4 1000 0.0020 _m = 0.250 0.0020 _m = 125 S cm ^2 mol ^ -1 Answer: 125
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