Question
The IUPAC name of the following compound is,
The IUPAC name of the following compound is,
A. 1, 1 - diethyl - 4 - methoxycyclohexane
The parent ring in the given structure is cyclohexane. The substituents attached to the ring are one methoxy group (-OCH_3) and two ethyl groups (-CH_2CH_3). According to IUPAC nomenclature rules, the ring must be numbered to give the lowest possible set of locants for the substituents. If we start numbering from the carbon with the two ethyl groups, the locant set is 1, 1, 4. If we start numbering from the carbon with the methoxy group, the locant set is 1, 4, 4. Comparing the two sets, (1, 1, 4) is lower than (1, 4, 4) at the first point of difference. Therefore, the carbon with the two ethyl groups is designated as position 1, and the carbon with the methoxy group is position 4. When writing the name, substituents are listed in alphabetical order. 'Ethyl' comes before 'methoxy' (multiplying prefixes like 'di' are ignored for alphabetization). Thus, the correct IUPAC name is 1,1-diethyl-4-methoxycyclohexane. Answer: 1, 1 - diethyl - 4 - methoxycyclohexane
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