MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

To find the IUPAC name of the given compound, we follow these steps: 1. Identify the principal functional group: The molecule contains a hydroxyl group (-OH) and a double bond. The hydroxyl group has higher priority, so it is the principal functional group and must be given the lowest possible locant. 2. Determine the longest carbon chain: The longest continuous carbon chain that contains both the -OH group and the double bond must be selected. Tracing from the rightmost ethyl group to the leftmost ethyl group gives a chain of 9 carbon atoms. Thus, the parent alkane is nonane. 3. Number the chain: We number the chain to give the principal functional group (-OH) the lowest possible number. Numbering from right to left: C1, C2: Ethyl group on the right (-CH_2-CH_3) C3: Carbon with a methyl substituent C4: Carbon with the -OH group C5, C6: Carbons of the double bond C7: Carbon with a methyl substituent C8, C9: Ethyl group on the left (-CH_2-CH_3) In this numbering, the -OH group is at position 4. If we numbered from left to right, the -OH group would be at position 6. Therefore, the right-to-left numbering is correct. 4. Identify substituents and their positions: - A methyl group at C-3. - A methyl group at C-7. - A double bond starting at C-5. - The hydroxyl group at C-4. 5. Assemble the name: Combining these parts, we get: 3,7-dimethyl + non + 5-en + 4-ol 3,7-dimethylnon-5-en-4-ol. Answer: 3,7-Dimethylnon-5-en-4-ol