MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

Reaction of 2-bromopentane with alcoholic KOH undergoes dehydrohalogenation (E2 elimination). CH_3-CH(Br)-CH_2-CH_2-CH_3 alc. KOH, CH_3-CH=CH-CH_2-CH_3 + CH_2=CH-CH_2-CH_2-CH_3 According to Zaitsev's rule, the more substituted alkene is formed as the major product. Pent-2-ene is a disubstituted alkene, whereas pent-1-ene is a monosubstituted alkene. Thus, pent-2-ene is the major product. Answer: Pent-2-ene