MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The reaction of propene with HBr in the presence of peroxide proceeds via a free radical mechanism, known as the peroxide effect or anti-Markovnikov addition. The peroxide undergoes homolytic cleavage to form alkoxy radicals, which then abstract a hydrogen atom from HBr to generate a bromine radical (Br^ ). The bromine radical adds to the less substituted carbon atom of the double bond in propene to generate a more stable secondary free radical: CH_3-CH=CH_2 + Br^ CH_3- C H-CH_2Br The secondary free radical then abstracts a hydrogen atom from another molecule of HBr to form the final product: CH_3- C H-CH_2Br + HBr CH_3-CH_2-CH_2Br + Br^ The major product formed is 1-bromopropane. Answer: 1 - Bromopropane