Quantrex Academy · Free MHT CET PYQ solutions
MHT CET Chemistry Hydrocarbons 2026 MHT CET 2026 (15 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

Identify the compound formed when But-2-ene is treated with KMnO _4 in dilute H _2 SO _4.

Options

  1. A. Butanoic acid
  2. B. Acetic acid
  3. C. Butanal
  4. D. Butanol

Answer

B. Acetic acid

Step-by-step solution

But-2-ene has the structure CH _3- CH = CH - CH _3. When treated with acidic KMnO _4 ( KMnO _4 in dilute H _2 SO _4), it undergoes oxidative cleavage. The strong oxidizing agent completely breaks the carbon-carbon double bond, oxidizing each of the resulting fragments into a carboxylic acid. CH _3- CH = CH - CH _3 KMnO _4, H ^+ 2 CH _3 COOH The product formed is acetic acid (ethanoic acid). Answer: Acetic acid

Practice more on Quantrex App →

Related: Chemistry — Hydrocarbons · All PYQ Banks