MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

For a weak monobasic acid, the dissociation constant K_a is given by Ostwald's dilution law: K_a = C ^2 where C is the concentration and is the degree of dissociation. Given C_1 = 0.05 M and _1 = 4\% = 0.04: K_a = 0.05 (0.04)^2 = 0.05 0.0016 = 8 10^ -5 For the new concentration C_2 = 0.1 M, let the degree of dissociation be _2: K_a = C_2 _2^2 8 10^ -5 = 0.1 _2^2 _2^2 = 8 10^ -5 0.1 = 8 10^ -4 _2 = 8 10^ -4 = 2.828 10^ -2 The percent dissociation in 0.1 M solution is 2.828\%. Answer: 2.828\%