Question
Calculate the pOH of 0.01 M monobasic acid that is completely dissociated, at 298 K.
MHT CET
Chemistry
Ionic Equilibrium
2026
MHT CET 2026 (20 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 02
- B. 12
- C. 03
- D. 11
Answer
B. 12
Step-by-step solution
For a completely dissociated monobasic acid, the concentration of hydrogen ions is equal to the concentration of the acid. [H^+] = 0.01 M = 10^ -2 M The pH of the solution is calculated as: pH = - [H^+] = - (10^ -2 ) = 2 At 298 K, the relationship between pH and pOH is: pH + pOH = 14 Substituting the value of pH: pOH = 14 - 2 = 12 Answer: 12
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