Question
Calculate the molar concentration of weak monobasic acid if K_a = 1.8 10^ -5 and degree of dissociation is 0.01 ?
Calculate the molar concentration of weak monobasic acid if K_a = 1.8 10^ -5 and degree of dissociation is 0.01 ?
A. 1.8 10^ -1
For a weak monobasic acid, the dissociation constant is given by: K_a = C ^2 1- Since = 0.01, which is very small compared to 1, we can approximate 1- 1. K_a = C ^2 Rearranging for C: C = K_a ^2 Substituting the given values: C = 1.8 10^ -5 (0.01)^2 C = 1.8 10^ -5 10^ -4 C = 1.8 10^ -1 M Answer: 1.8 10^ -1
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