A weak base is 1.3\% dissociated in its aqueous solution. If K_b for weak base is 1.69 10^ -5 at 298 K. Find the concentration of aqueous solution of weak base.

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Correct answer: B. 0.1 M

For a weak base, the dissociation constant K_b is given by Ostwald's dilution law: K_b = C ^2 1 - Since the degree of dissociation = 1.3\% = 0.013 is very small ( 1), we can approximate 1 - 1. The expression simplifies to: K_b = C ^2 Rearranging for concentration C: C = K_b ^2 Substituting the given values K_b = 1.69 10^ -5 and = 0.013: C = 1.69 10^ -5 (0.013)^2 C = 1.69 10^ -5 1.69 10^ -4 C = 10^ -1 = 0.1 M Answer: 0.1 M

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