Question
An organic monobasic acid has dissociation constant 1.96 10^ -8 . What is its percentage dissociation in 0.01 M solution ?
MHT CET
Chemistry
Ionic Equilibrium
2026
MHT CET 2026 (18 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1.40\,\%
- B. 0.14\,\%
- C. 2.4\,\%
- D. 0.19\,\%
Answer
B. 0.14\,\%
Step-by-step solution
For a weak monobasic acid, the dissociation constant is given by K_a = C ^2, where is the degree of dissociation and C is the concentration. = K_a C Substituting the given values K_a = 1.96 10^ -8 and C = 0.01 M: = 1.96 10^ -8 0.01 = 1.96 10^ -6 = 1.4 10^ -3 Percentage dissociation = 100 Percentage dissociation = 1.4 10^ -3 100 = 0.14\,\% Answer: 0.14\,\%
Related: Chemistry — Ionic Equilibrium · All PYQ Banks