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MHT CET Chemistry Ionic Equilibrium 2026 MHT CET 2026 (18 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

The solubility of salt AX _2 is 6 10^ -12 \ mol dm ^ -3 . What is solubility product of the salt ?

Options

  1. A. 2.06 10^ -24
  2. B. 2.48 10^ -24
  3. C. 4.32 10^ -34
  4. D. 8.64 10^ -34

Answer

D. 8.64 10^ -34

Step-by-step solution

The dissociation of the salt AX _2 is given by: AX _2 A ^ 2+ + 2 X ^- Let the solubility of the salt be s. [ A ^ 2+ ] = s [ X ^-] = 2s The solubility product K_ sp is: K_ sp = [ A ^ 2+ ][ X ^-]^2 = (s)(2s)^2 = 4s^3 Given s = 6 10^ -12 \ mol dm ^ -3 , substituting this value: K_ sp = 4 (6 10^ -12 )^3 K_ sp = 4 216 10^ -36 K_ sp = 864 10^ -36 = 8.64 10^ -34 Answer: 8.64 10^ -34

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