MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The dissociation of the salt AB_2 is given by: AB_2 A^ 2+ + 2B^- Let the solubility of the salt be S. The equilibrium concentrations are: [A^ 2+ ] = S [B^-] = 2S The solubility product K_ sp is: K_ sp = [A^ 2+ ][B^-]^2 K_ sp = (S)(2S)^2 = 4S^3 Given S = 1 10^ -6 \ mol/dm ^3, substituting this value: K_ sp = 4(1 10^ -6 )^3 K_ sp = 4 10^ -18 Answer: 4 10^ -18