Question
The solubility of sapringly soluble salt AB _2 is 18 78 10^ -4 g/dm ^3 What is its solubility product ? (Molar mass of AB _2 = 187 8 g mol ^ -1 )
MHT CET
Chemistry
Ionic Equilibrium
2026
MHT CET 2026 (17 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 2 10^ -15
- B. 4 10^ -15
- C. 6 10^ -15
- D. 8 10^ -15
Answer
B. 4 10^ -15
Step-by-step solution
Solubility S in mol dm ^ -3 is calculated by dividing the solubility in g dm ^ -3 by the molar mass. S = 18 78 10^ -4 187 8 = 10^ -5 mol dm ^ -3 The dissociation of the salt AB _2 is given by: AB _2 A ^ 2+ + 2 B ^ - The solubility product K_ sp is: K_ sp = [ A ^ 2+ ][ B ^ - ]^2 = (S)(2S)^2 = 4S^3 Substituting the value of S: K_ sp = 4 (10^ -5 )^3 = 4 10^ -15 Answer: 4 10^ -15
Related: Chemistry — Ionic Equilibrium · All PYQ Banks