Question
What is the solubility product of binary sparingly soluble salt BA if 100 mL saturated solution of salt consist 10^ -4 moles at room temperature?
MHT CET
Chemistry
Ionic Equilibrium
2026
MHT CET 2026 (15 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1 10^ -4
- B. 1 10^ -6
- C. 1 10^ -8
- D. 1 10^ -10
Answer
B. 1 10^ -6
Step-by-step solution
The solubility S of the salt is the number of moles dissolved per litre of the saturated solution. Given moles of salt = 10^ -4 and volume = 100 mL = 0.1 L. S = 10^ -4 0.1 = 10^ -3 mol L^ -1 For a binary salt BA, the dissociation is: BA B^ + + A^ - The solubility product K_ sp is given by: K_ sp = [B^ + ][A^ - ] = S S = S^2 Substituting the value of S: K_ sp = (10^ -3 )^2 = 1 10^ -6 Answer: 1 10^ -6
Related: Chemistry — Ionic Equilibrium · All PYQ Banks