Question
The solubility of sparingly soluble salts MX _1, MX _2 and MX _3 is 1 10^ -3 mol/L. Hence, their respective solubility products are
MHT CET
Chemistry
Ionic Equilibrium
2026
MHT CET 2026 (15 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1 10^ -6 , 4 10^ -9 and 27 10^ -12
- B. 1 10^ -9 , 4 10^ -9 and 32 10^ -12
- C. 1 10^ -9 , 8 10^ -8 and 32 10^ -12
- D. 1 10^ -6 , 8 10^ -8 and 27 10^ -12
Answer
A. 1 10^ -6 , 4 10^ -9 and 27 10^ -12
Step-by-step solution
For the salt MX _1 (type AB ): MX _1 M ^+ + X ^- K_ sp = S^2 Substituting S = 1 10^ -3 mol/L: K_ sp = (1 10^ -3 )^2 = 1 10^ -6 For the salt MX _2 (type AB _2): MX _2 M ^ 2+ + 2 X ^- K_ sp = (S)(2S)^2 = 4S^3 Substituting S = 1 10^ -3 mol/L: K_ sp = 4(1 10^ -3 )^3 = 4 10^ -9 For the salt MX _3 (type AB _3): MX _3 M ^ 3+ + 3 X ^- K_ sp = (S)(3S)^3 = 27S^4 Substituting S = 1 10^ -3 mol/L: K_ sp = 27(1 10^ -3 )^4 = 27 10^ -12 Answer: 1 10^ -6 , 4 10^ -9 and 27 10^ -12
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