MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

For a weak base BOH, the dissociation reaction is BOH B^+ + OH^-. Let the initial concentration be C and the degree of dissociation be . At equilibrium, the concentrations are [BOH] = C(1- ), [B^+] = C , and [OH^-] = C . The base dissociation constant K_b is given by K_b = [B^+][OH^-] [BOH] = C C C(1- ) = C ^2 1- . For a weak base, is very small compared to 1, so 1- 1. Thus, K_b C ^2 = K_b C . Therefore, the degree of dissociation of a weak base is inversely proportional to the square root of its concentration. Answer: The degree of dissociation of a weak base is inversely proportional to square root of its concentration.