MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

Let the solubility of BaSO _4 be s mol/ dm ^3. The dissociation reaction is: BaSO _4(s) Ba ^ 2+ (aq) + SO _4^ 2- (aq) The solubility product K_ sp is given by: K_ sp = [ Ba ^ 2+ ][ SO _4^ 2- ] = s s = s^2 Substituting the given value of K_ sp : s^2 = 1.0 10^ -10 s = 1.0 10^ -5 mol/ dm ^3 To find the solubility in g/ dm ^3, multiply the molar solubility by the molar mass of BaSO _4: Solubility = s Molar mass Solubility = 1.0 10^ -5 233 Solubility = 2.33 10^ -3 g/ dm ^3 Answer: 2.33 10^ -3 g/ dm ^3