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MHT CET Chemistry p Block Elements (Group 15, 16, 17 & 18) 2026 MHT CET 2026 (11 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Match the Xenon compounds in Column-1 with its structure in Column-II. Column – I Column – II (a) XeF _4 (i) pyramidal (b) XeF _6 (ii) square planar (c) XeOF _4 (iii) distorted octahedral (d) XeO _3 (iv) square pyramidal

Options

  1. A. (a) - (ii), (b) - (iii), (c) - (i), (d) - (iv)
  2. B. (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
  3. C. (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
  4. D. (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

Answer

D. (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

Step-by-step solution

For XeF _4: Xenon has 8 valence electrons. It forms 4 single bonds with fluorine atoms and has 2 lone pairs. The hybridization is sp^3d^2 and the shape is square planar. Thus, (a) matches (ii). For XeF _6: Xenon forms 6 single bonds with fluorine atoms and has 1 lone pair. The hybridization is sp^3d^3 and the shape is distorted octahedral. Thus, (b) matches (iii). For XeOF _4: Xenon forms 4 single bonds with fluorine atoms, 1 double bond with oxygen, and has 1 lone pair. The hybridization is sp^3d^2 and the shape is square pyramidal. Thus, (c) matches (iv). For XeO _3: Xenon forms 3 double bonds with oxygen atoms and has 1 lone pair. The hybridization is sp^3 and the shape is pyramidal. Thus, (d) matches (i). The correct matching is (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i). Answer: (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

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