Question
What is oxidation state of oxygen in OF _2 and in KO _2 respectively?
MHT CET
Chemistry
Redox Reactions
2026
MHT CET 2026 (13 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. +2 and +1
- B. +2 and -1/2
- C. +1 and -1/2
- D. -2 and -1
Answer
B. +2 and -1/2
Step-by-step solution
In OF _2, fluorine is more electronegative than oxygen and always has an oxidation state of -1. Let the oxidation state of oxygen in OF _2 be x. x + 2(-1) = 0 x = +2 In KO _2, potassium is an alkali metal and always has an oxidation state of +1. Let the oxidation state of oxygen in KO _2 be y. +1 + 2y = 0 y = -1/2 The oxidation states of oxygen in OF _2 and KO _2 are +2 and -1/2 respectively. Answer: +2 and -1/2
Related: Chemistry — Redox Reactions · All PYQ Banks