Question
In ionic solid, anions are arranged in hcp array and cations occupy 1 2 tetrahedral voids. What is the formula of ionic compound ? [Consider A = Cation ; B = anion]
MHT CET
Chemistry
Solid State
2026
MHT CET 2026 (19 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. AB _2
- B. AB
- C. A _2 B
- D. AB _3
Answer
B. AB
Step-by-step solution
Let the number of anions (B) forming the hcp array be N. The total number of tetrahedral voids generated in the lattice is 2N. Since cations (A) occupy 1 2 of the tetrahedral voids, the number of cations (A) is 1 2 2N = N. The ratio of the number of cations (A) to the number of anions (B) is N : N = 1 : 1. Therefore, the formula of the ionic compound is AB . Answer: AB
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