Question
Gold crystallizes as fcc unit cell, the edge length of unit cell is 408 pm. What is the radius of gold atom?
MHT CET
Chemistry
Solid State
2026
MHT CET 2026 (19 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 86.6 pm
- B. 115.4 pm
- C. 144.2 pm
- D. 175.2 pm
Answer
C. 144.2 pm
Step-by-step solution
For a face-centered cubic (fcc) unit cell, the relationship between the edge length a and the radius of the atom r is given by: 4r = 2 a r = a 2 2 Given a = 408 pm: r = 408 2 2 = 204 2 = 102 2 pm Substituting 2 = 1.414: r = 102 1.414 = 144.228 pm 144.2 pm Answer: 144.2 pm
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