Question
Calculate the number of atoms present in 1\ g metal that forms simple unit cell structure if product of density and volume of unit cell is 66.5 10^ -24 \ g
MHT CET
Chemistry
Solid State
2026
MHT CET 2026 (18 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1.504 10^ 22
- B. 3.419 10^ 22
- C. 2.516 10^ 22
- D. 2.018 10^ 22
Answer
A. 1.504 10^ 22
Step-by-step solution
For a simple cubic unit cell, the number of atoms per unit cell is Z = 1. The mass of one unit cell is equal to the product of its density and volume. Mass of one unit cell = V = 66.5 10^ -24 g . Since there is 1 atom per unit cell, the mass of one atom is 66.5 10^ -24 g . The number of atoms in 1 g of the metal is given by: Number of atoms = Total mass Mass of one atom Number of atoms = 1 66.5 10^ -24 Number of atoms = 0.015037 10^ 24 Number of atoms 1.504 10^ 22
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