Question
Calculate the number of atoms in 1 g metal that forms bcc crystal structure [ a^3 = 6 6 10^ -22 g ]
Calculate the number of atoms in 1 g metal that forms bcc crystal structure [ a^3 = 6 6 10^ -22 g ]
C. 3 03 10^ 21
The mass of one unit cell is given by the product of its density and volume: Mass of unit cell = a^3 = 6 6 10^ -22 g For a body-centered cubic (bcc) crystal structure, the number of atoms per unit cell is Z = 2. Mass of one atom = Mass of unit cell Z = 6 6 10^ -22 2 = 3 3 10^ -22 g The number of atoms in 1 g of the metal is: Number of atoms = 1 g Mass of one atom = 1 3 3 10^ -22 = 3 03 10^ 21 Answer: 3 03 10^ 21
Related: Chemistry — Solid State · All PYQ Banks