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MHT CET Chemistry Solid State 2026 MHT CET 2026 (15 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Calculate the number of atoms present in 1.625 g metal if it forms bcc unit cell structure. [ a^3 = 3.25 10^ -22 \ g ]

Options

  1. A. 2.0 10^ 22
  2. B. 1.5 10^ 22
  3. C. 2.5 10^ 22
  4. D. 1.0 10^ 22

Answer

D. 1.0 10^ 22

Step-by-step solution

Mass of one unit cell is given by a^3 = 3.25 10^ -22 g. For a body-centered cubic (bcc) structure, the number of atoms per unit cell is Z = 2. Mass of one atom = Mass of unit cell Z = 3.25 10^ -22 2 = 1.625 10^ -22 g. Total number of atoms in 1.625 g of the metal = Total mass Mass of one atom Number of atoms = 1.625 1.625 10^ -22 = 1.0 10^ 22 Answer: 1.0 10^ 22

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