Question
Pt has FCC structure with an edge length of unit cell 392 pm. What is the radius of Pt?
MHT CET
Chemistry
Solid State
2026
MHT CET 2026 (11 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 138.6 pm
- B. 175.6 pm
- C. 185.6 pm
- D. 205.6 pm
Answer
A. 138.6 pm
Step-by-step solution
For an FCC (face-centered cubic) structure, the relationship between the edge length a and the atomic radius r is given by: 4r = 2 a r = a 2 2 Given a = 392 pm: r = 392 2 2 = 196 2 r = 98 2 Using 2 1.414: r = 98 1.414 = 138.57 pm 138.6 pm Answer: 138.6 pm
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