Calculate the mass of nonvolatile solute dissolved in 0.3 dm^3 water having osmotic pressure 0.1 atm at 300K. [Molar mass of solute = 328 g mol^ -1 , R = 0.082 dm^3atm K^ -1 mol^ -1 ]

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Correct answer: A. 0.4 g

The osmotic pressure is given by the formula: = W M V R T Rearranging for the mass of the solute W: W = M V R T Substituting the given values: W = 0.1 328 0.3 0.082 300 W = 9.84 24.6 W = 0.4 g Answer: 0.4 g

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